Which value for x makes the open sentence true? 6 • 7 – 5x + x2 ≥ x3 + x2
1 answer:
<span>6●7–5x+<span>x2</span>≥<span>x3</span>+<span>x2</span></span>
Lets plug in 3:
<span>6●7–5(3)+<span>32</span>≥<span>33</span>+<span>32</span></span>
Multiply -5 * 3:
<span>6●7–15+<span>32</span>≥<span>33</span>+<span>32</span></span>
Simplify all exponents:
<span>6●7–15+9≥27+9</span>
Multiply 6 * 7:
<span>42–15+9≥27+9</span>
Subtract 42 - 15:
<span>27+9≥27+9</span>
Add 27 + 9:
<span>36≥27+9</span>
Add 27 + 9:
<span>36≥36</span><span>
So 3 is correct.</span>
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