Question;
Assumption:
Let us assume Brandon's running speed is = 18.30 and
Ruben's running speed is = 16.50 and
Answer:
The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;
Brandon → Y₁ = 18.3·X₁ and
Ruben → Y₂ = 16.5·X₂
Step-by-step explanation:
The equation is of the form
Y = 17.45·X
That is Amy ran Y meters in X seconds
Therefore we have
or the value 17.45 is the running speed of Amy
Therefore, where the running speed of Brandon is 18.30 and the running speed of Ruben is 16.50 we have
Y meters ran by Brandon in X seconds given by
Y₁ = 18.3·X₁ and
For Ruben we have Y meters ran in X seconds given by
Y₂ = 16.5·X₂.
Answer:
27
Step-by-step explanation:
If k/3 = 9
K must be 27
because 9*3=27
and to check we can do
27/3
and 27/3 = 7
Let's get all of the distances lined up:
= home to office
to a restaurant
back to the office
= store
= back home
So then we just add up all of the numbers. However we need to make sure that there is a common denominator. Let's make the common denominator 12, since that is a common factor to all of the denominators in the problem:
= home to office
to a restaurant
back to the office
= store
= back home
Then let's add them up:
This does not reduce to a nice number, however, we can simplify to:
Answer:
a = 5
Step-by-step explanation:
3 (a + 3) + 6 = 30
Use the distibutive property to multiply 3 by a + 3
3a + 9 + 6 = 30
Add 9 and 6 to get 15
3a + 15 = 30
Subtract 15 from both sides
3a = 30 - 15
Subtract 15 from 30 to get 15.
3a = 15
Divide both sides by 3.
a = 15/3
Divide 15 by 3 to get 5
a = 5
