What is this answer?

Translate Q(3,-8) using (x,y)—>(x-6, y + 2)

valentinak56 [21]

Hope this helps bye bye

6 0

2 years ago

Nikki has 3 pieces of yarn. the first piece is 5/6 feet long the second piece is 5/3 feet long and the third piece is 3/2 oder s

xenn [34]

I think you are asking to sort them according to the shortest to longest in length. For this, it would be helpful to write the fraction into decimal. The equivalent values are as follows:

5/6 = 0.83
5/3 = 1.67
3/2 = 1.50

Therefore, the correct sorting would be as follows:

first yarn
third yarn
second yarn

Hope this answers the question. Have a nice day.

4 0

2 years ago

What is the probability that at least 2 of 3 randomly selected students are in th3 band

Nutka1998 [239]

The estimated probability would be 0.1... I had this test yesterday. hope this helps

4 0

3 years ago

The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind

Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .