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3 years ago

Help me please thank you.

Mathematics

2 answers:

Wewaii [24]3 years ago

7 0

C is the correct answer.

Work used to work out problem:

I substitued numbers until I found the correct input and output

300+10(75)=1050/75

which equal 14

Please vote my answer branliest! Thanks.

Alexus [3.1K]3 years ago

4 0

J would have to say that the answer is d. im sorry if im wrong.

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Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s

garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

$X=$ Customers that arrive within the hour

and since $X$ follows a Poisson distribution with mean $\alpha$ = 7

Therefore,

$E(X)= 7$

$& V(X)=7$

Let $Y =$ the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

$Y=10X$

For a random variable $X$ and a constant $c$ ,

$E(cX)=cE(X)\\V(cX)=c^2V(X)$

Thus,

$E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700$

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution $Y$ is,

$p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}$

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

$P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7} .\frac{1}{10} \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002$

0.002 is small enough, and the function $\frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}$ gets even smaller when $k$ increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0

2 years ago

Find the height of the tree

NeX [460]

Use the property of similarity of triangles =》the corresponding sides of a triangle should be in the same ratio.

Take the missing side as 'x'.

The corresponding sides here are,

■ 7 & 14 ft

■ 5 & x ft

7/14 = 5/x

7x = 5 × 14 (cross multiplication)

7x = 70

x = 70/7

x = 10 ft

Height of the tree = 10 ft.

_____

Hope it helps ⚜

8 0

2 years ago

Carson needs 3 quarts of water to make fruit punch, but has only a 1-cup measuring cup. She knows there are 2 cups in 1 pint, an

USPshnik [31]

Answer:

Step-by-step explanation:

3 quarts is 6 pints

6 pints is 12 cups

if there is 4 cups in a quart then 4x3=12

4 0

2 years ago

Matthew is standing near a flag pole as shown in the picture. There is a support wire that has been place on the ground to the t

mash [69]

Answer:

Step-by-step explanation:

10 x 6 is what?

Took the test :p

7 0

2 years ago

Please help me I tried to do it

anyanavicka [17]

You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277
so if i did it right you should get n=277

8 0

3 years ago