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3 years ago

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Tickets to a school play cost $3 for students and $8 for adults. on opening night, $1840 was collected and 360 tickets sold. use

substitution to solve a system of equations to find how many of each kind of ticket were sold? enter your answers in the boxes.

1 answer:

Pachacha [2.7K]3 years ago

5 0

Answer:

240a (adults) 120s ( students ) hope that helped

Step-by-step explanation:

3/360 8/1840

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Graph the equation.

Natalija [7]

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Step-by-step explanation:

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2 years ago

What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

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2 years ago

Please help me I don’t have a lot of time

sp2606 [1]

Answer:

I believe the answer is d

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2 years ago

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ikadub [295]

Answer: x=112

Step-by-step explanation: If you add 35 and 33 you would get 68 and if you subtract 68 from 180 you will get 112. I hope this helps!

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3 years ago

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3 years ago