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3 years ago

What is the probability that your birthday will fall on saturday or sunday

Mathematics

2 answers:

n200080 [17]3 years ago

7 0

I got 2/7 for this one.

iogann1982 [59]3 years ago

3 0

Um 2 outta seven or a 28.57%

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A plumbing contractor receives proceeds of $4,713.54 on a 12.5% simple discount note with a face value of $5,000. Find the time

kolbaska11 [484]

I = Prt
t = I/(Pr)
.. = (5000 -4713.54)/(5000*0.125)
.. = 165/360

The time period of the note is 165 days.

8 0

3 years ago

A flower shop makes 5 bouquets with 18 flowers in each bouquet. They make 7 bouquets with 12 flowers in each bouquet.

Anettt [7]

Answer:

174

Step-by-step explanation:

thanks for the help guys

7 0

2 years ago

Decide which calculation shows the correct way to find 0.3 - 0.006 and explain your reasoning.

kirza4 [7]

D : 0.300- 0.006 is correct

A is wrong bec 0.3 doesn’t have the extra 0’s in the end

B is wrong bec the decimal places aren’t aligned

C is wrong bec again, the decimal places aren’t aligned

6 0

2 years ago

Read 2 more answers

What letter on this number line represents -(3/2)?

makvit [3.9K]

Step-by-step explanation:

B Represent $\sf{ - ( \dfrac{3}{2}) }$

4 0

2 years ago

Let f(x) = cx^k be a power function such that f(13) is four times the size of f(1). What is the power k?

Ivenika [448]

Answer:

0.540

Step-by-step explanation:

Hi there,

To get started in order to solve this, please recall the property of logarithms.

This question is a bit tricky, but doable. Best way to solve this is first compare the two functions:

$f(x) = cx^{k} \\ f(13)=4f(1)$

Now, let's see what the function gives at 13 and 1:

$f(13)=c13^{k}\\f(1)=c1^{k}$

Something to recognize is that 1 to the power of <em>anything</em> is just 1, so f(1) is reduced to:

$f(1)=c$ We are making progress!

Next, we can set both f(13) forms equivalent to each other, watch this:

$f(13)=f(13) = 4f(1)$ but we know what f(1) is equal to, and let's substitute our knowns:

$c13^{k}=4c1^{k} = 4c$ the c constant on both left and right side cancel out:

$13^{k}=4$ Now, take the logarithm form of both side of the equation. I used natural log, but you can also use common logs:

$ln(13^{k})=ln(4)$ ⇒ $k*ln(13)=ln(4)$ this was performed using <em>the power log rule. </em>

Isolate k:

$k=\frac{ln(4)}{ln(13)} =0.540$ using a calculator.

If you liked this solution, hit Thanks or give a rating!

thanks,

8 0

2 years ago