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nika2105 [10]
3 years ago
9

What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

The mass  of 0.7891 mol  of  ferric  oxide (Fe2O3)  is  125.94 grams


 <u><em>calculation</em></u>

mass of Fe2O3 is calculated using   moles   Fe2O3/ molar  mass of Fe2O3  formula

moles of Fe2O3  = 0.7891  moles

molar  mass  of Fe2O3=   (55.8 x2)  + (16 x3)  =159.6 g/mol


mass is therefore =0.7891 mol  x 159.6 g/mol=125.94 grams

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A = εcl ------(1)

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Step 1: Calculate the concentration of the diluted Fe3+ standard

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