Answer:
nvm its 15
Step-by-step explanation:
Answer:
A C
Step-by-step explanation:
A
A is true.The numerator does have 3 terms. The constant term (the 3 at the end) is still a term and counts as a term.
B
A constant term does not count as a coefficient so b is not right, just as you have indicated by not underlining it.
C
C is true. In fact, 2 is the leading coefficent of the denominator.
D
Either A is true or D is, but I don't think they both are. You need a modifier to claim that D is true. If the statement said the numerator has <em>at least </em>2 terms then both A and D would be true. Without the at least, you have to pick one and the one I choose is A
E
This is the tough one. Very sticky. You would think it is true, but it isn't. A constant term is not a coefficient. Coefficients only count when they are with "x"s.
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.
Answer:
1134.62 (THE SUM OF 20 TERMS)
Step-by-step explanation:
First we write out our given information:
a8=2a2
a11=18
an is an arithmetic sequence.
Where here an means the nth term of our sequence.
What does an arithmetic sequence mean? It means to get to the next term in your sequence you add a constant (c) each time:
an+1=an+c
Equivalently:
an+1−an(n+1)−n=c
So an is of slope c (c2 is another constant):
an=cn+c2
Where here c2=a0 (Substitute in n=0 and see why that has to be the case if we let a0 exist)
Now we use the other given information to try to come up with a solution.
Let n=2:
a2=2c+c2
Let n=8, using the above equation we have:
a8=8c+c2=2a2=4c+2c2
Let n=11
a11=18
a11=11c+c2
But a11−a8=(11c+c2)−(8c+c2)=3c
Hence, a11=3c+a8
a11=3c+4c+2c2=18
a11=3c+8c+c2=18
It looks to be 29, if the rule is to add 3z
