Answer:



Step-by-step explanation:
<u>Given:</u>



<u>Solve for </u>
<u> in the 1st equation:</u>



<u>Substitute the value of </u>
<u> into the 2nd equation and solve for </u>
<u>:</u>






<u>Substitute the value of </u>
<u> into the 3rd equation and solve for </u>
<u>:</u>






<u>Plug </u>
<u> into the solved expression for </u>
<u> and evaluate to solve for </u>
<u>:</u>



<u>Plug </u>
<u> into the solved expression for </u>
<u> and evaluate to solve for </u>
<u>:</u>




Therefore:



Answer:
4x+9 if that's not what u needed I can graph it for you too
W= 7
38=2w+2(12)
/
38=2w + 24
-24 -24
14=2w
divid by 2 divid by 2
7=w
Answer:
6x² + 15
6
Step-by-step explanation:
Let the number be x.
"the square of a number"
x²
"the product of 6 and the square of a number"
6x²
"the product of 6 and the square of a number plus 15"
6x² + 15
The coefficient is the number that multiplies the variable, so it is 6.
For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>