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aksik [14]
3 years ago
6

284+ 887 nearest hundred

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0
300+900=1200 or 284+887=1171=1200
so the answer to the nearest hundred would be 1200
lana66690 [7]3 years ago
6 0
1,200 would be your answer
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A large company claims that the average age of their employees is 32 years, with a standard deviation of 4 years. The average ag
4vir4ik [10]

Given that average age of employees of a large company is Normal

X - average age of employees

X:N(32,4)

The average age of employees in sales dept is 27 years.

Prob that an employee, chosen at random, will be younger than 27 years.

= P(X<27)

Let us convert x into Z

Z = (x-32)/4 = -5/4 = -1.25

Reqd prob = P(Z<-1.25) =0.5-0.3925

= 0.1075

Hence 10.56% is the correct answer.

3 0
3 years ago
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The submarine is 217 feet below sea level. Identify the integer
Sever21 [200]

Answer:

okay

Step-by-step explanation:

6 0
2 years ago
the function t(x)=4x+3 determines how many cans of hot sauce a food truck needed to stock on board where x is the number of shif
castortr0y [4]
First we need to calculate t(4) because x=4 for 4 shifts.
t(4) = 4*4 +3 = 19
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Answer is 43
7 0
3 years ago
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Consider the following confidence interval interpretation: We are 98% confident that the true mean laptop screen size is between
GalinKa [24]

Answer:

Incorrect

Step-by-step explanation:

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or 98% of the laptop have screen size between 19.2 and 21.4 inches

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7 0
3 years ago
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
2 years ago
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