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AlladinOne [14]
3 years ago
6

30 Points!!! Please Help (Surface Area)

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0
Multiply base x height then divide by 2 if finding surface are if finding volume multiple base x height x width and divide by 3
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You conduct a quality check after running 350 parts 49 of the parts do not need this specifications what percent of the parts do
zepelin [54]

Answer:

14%

Step-by-step explanation:

<em><u>49 parts of 350 parts</u></em> do not need specifications...

= 49/350

So, 49/350 = x/100

= <u>49(100) = 350x</u>

= 4900 = 350x

= 4900/350 = x

x = 14%

6 0
3 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
What equals 44 in multiplication
KATRIN_1 [288]
There are numerous ways two numbers can be multiplied to get 44. Nothing specific has been asked in this question and so i am giving all the answers below.

4 x 11 = 44
2 x 22 = 44
1 x 44 = 44
4 0
3 years ago
Read 2 more answers
Plz help will mark brainliest
levacccp [35]

Answer:

-2

5

Step-by-step explanation:

1.

-2^{2}-3(-2)-10 \\4+6-10\\10-10\\0

2.

5^{2} -3(5)-10\\25-15-10\\10-10\\0

7 0
3 years ago
Read 2 more answers
Help please... I'll give brainliest​
kherson [118]

Answer:

the answer is -16

Step-by-step explanation:

y=1/4 x -16 +3 = -1

5 0
3 years ago
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