Answer:
Henry is 18 and Paul is 7
Step-by-step explanation:
I figured it out in my head.
18 yrs and
7 years
Let Henry’s age be A and Paul’s age be B
Given Henry’s age A is 10 yrs less than 4 times Paul’s age B.
That’s
A =4 x B - 10
A = 4B - 10
The sum of their ages is equal to 25
A + B = 25
Therefore,we no now have to equations
1. A = 4B - 10
2. A + B = 25
Now put 4B - 10 in place of A in equation 2
We have
4B - 10 + B = 25
This can also be written as
4B + B - 10 = 25
5B - 10 = 25
Add 10 to both sides
5B - 10 + 10 = 25 + 10
5B = 35
Divide both sides by 5
5B/5 = 35/5
B = 7
Paul’s age = 7 yrs
Recall A = 4B - 10
and B= 7
Therefore,
A = 4 x 7 - 10
A = 28 - 10
A = 18
Henry’s age = 18 yrs
Their ages are 18 yrs and 7 years
5 units
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
all work is pictured and shown
40mph
(60mph+20mph)/2
40
8/3
There are thirty-nine palindromic numbers between 10 and 400.
Listed, they are: 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, 212, 222, 232, 242, 252, 262, 272, 282, 292, 303, 313, 323, 333, 343, 353, 363, 373, 383, and 393.