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Aliun [14]
3 years ago
14

Henry’s age is 10 years less than 4 times Paul’s age. If the sum of their ages is equal to 25 years, find the age of each boy.

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

Henry is 18 and Paul is 7

Step-by-step explanation:

I figured it out in my head.

uysha [10]3 years ago
6 0

Answer:

18 yrs and

7 years

Step-by-step explanation:

Let Henry’s age be A and Paul’s age be B

Given Henry’s age A is 10 yrs less than 4 times Paul’s age B.

That’s

A =4 x B - 10

A = 4B - 10

The sum of their ages is equal to 25

That’s

A + B = 25

Therefore,we no now have to equations

1. A = 4B - 10

2. A + B = 25

Now put 4B - 10 in place of A in equation 2

We have

A + B = 25

4B - 10 + B = 25

This can also be written as

4B + B - 10 = 25

5B - 10 = 25

Add 10 to both sides

5B - 10 + 10 = 25 + 10

5B = 35

Divide both sides by 5

5B/5 = 35/5

B = 7

Paul’s age = 7 yrs

Recall A = 4B - 10

and B= 7

Therefore,

A = 4 x 7 - 10

A = 28 - 10

A = 18

Henry’s age = 18 yrs

Their ages are 18 yrs and 7 years

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Four less than 2 times the quantity of a number minus 3 is 12
svetlana [45]

Answer:

11.

Step-by-step explanation:

(2(n-3))-4=12

(2n-6)-4=12 <em>distribute</em>

2n-6-4=12

2n-10=12

2n=12+10 <em>isolate</em><em> </em><em>n</em><em> </em>

2n=22

2n÷2=22÷2

n=11

7 0
3 years ago
Emily read 24 fiction books and 2 nonfiction books. What is the ratio of the number of fiction books she read to the total numbe
dimulka [17.4K]

Answer:

26

Step-by-step explanation:i used a caluculator

3 0
2 years ago
Read 2 more answers
Mrs Tan bought 4 times as many pens as notebooks and each notebook cost $8.20 more than each pen. She spent $26 more on the book
lilavasa [31]
Let x be the cost of 1 pen
then cost of 1 notebook = x + 8.20

Let y be the number of pens Tan buys
then number of notebooks Tan buys = y/4

She spent $26 more on books than on pens which means

Cost of notebooks - Cost of pens = 26
(x + 8.20) * y/4 - xy = 26

Sinplifying it

(xy + 8.20y)/4 - xy = 26
(xy + 8.20y - 4xy)/4 = 26
8.20y - 3xy = 104

She spent $394 which means

Cost of notebooks + Cost of pens = 394
(x + 8.20) * y/4 + xy = 394

Simplifying it

(xy + 8.20y)/4 + xy = 394
(xy + 8.20y + 4xy)/4 = 394
8.20y + 5xy = 1576

Now, we have two equations,

(1) 8.20y - 3xy = 104
(2) 8.20y + 5xy = 1576

Now we need to find a third equation with either x or y as the subject of any of both the previous equations.

Let's make y the subject of (2) equation

8.20y + 5xy = 1576
y(8.20 + 5X) = 1576
(3) y = 1576/(8.20 + 5x)

Let's substitute the new value of y from (3) into (1) because we rearranged (2) to from (3)

8.20y - 3xy = 104
y(8.20 - 3x) = 104
y = 104/(8.20 - 3x)
1576/(8.20 + 5x) = 104/(8.20 - 3x)
1576 * (8.20 - 3x) = 104 * (8.20 + 5x)
12923.2 - 4728x = 852.8 + 520x
12923.2 - 852.8 = 4728x + 520x
12070.4 = 5248x
12070.4/5248 = x
x = 2.3

Now find the value of y by substituting the value of x in either equation, preferably (3)

y = 1576/(8.20 + 5x)
y = 1576/(8.20 + 5 * (2.3))
y = 80

Therefore cost of 1 notebook = x + 8.20 = 2.3 + 8.20 = $10.50

8 0
3 years ago
Michael is paid $9 per hour to work at the movie theater and $7 per hour when he helps his aunt at her bakery. Michael cannot wo
Murljashka [212]
If he works 32 hrs at the movie theater = $288 > $251


4 0
3 years ago
Read 2 more answers
I am confused about how to do this problem and I don't think it should be hard, but I just don't know how to approach it, so if
solniwko [45]

Answer:

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) (0.875, 0.676)

d) (0, 1.235)

Step-by-step explanation:

Set each term in the numerator and denominator equal to 0 and find r.

In the numerator:

r = 7/8, 5/9, or 6

In the denominator:

r = 9/5, 7/8, or -3

Zeros in the numerator that aren't in the denominator are r-intercepts.

Zeros in the denominator that aren't in the numerator are vertical asymptotes.

Zeros in both the numerator and the denominator are holes.

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) Evaluate m(r) at r = 7/8.  To do that, first divide out the common term (-8r + 7) from the numerator and denominator.

m(r) = (-9r+5)² (r−6)² / ( (-5r+9)² (r+3)² )

m(⅞) = (-9×⅞+5)² (⅞−6)² / ( (-5×⅞+9)² (⅞+3)² )

m(⅞) = (-23/8)² (-41/8)² / ( (37/8)² (31/8)² )

m(⅞) = (-23)² (-41)² / ( (37)² (31)² )

m(⅞) = 0.676

The hole is at (0.875, 0.676).

d) Evaluate m(r) at r = 0.

m(0) = (-9×0+5)² (0−6)² / ( (-5×0+9)² (0+3)² )

m(0) = (5)² (-6)² / ( (9)² (3)² )

m(0) = 1.235

The m(r)-intercept is (0, 1.235).

5 0
3 years ago
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