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V125BC [204]
4 years ago
14

pencils are sold in packages of 10 and erasers are sold in packages of 6 what is the least number of pencils and erasers you can

buy so that there is one pencil and eraser with none leftover
Mathematics
2 answers:
Keith_Richards [23]4 years ago
6 0
6packs of pencils and 10packs of eraser's
harkovskaia [24]4 years ago
5 0

Answer: There should be 3 pencils and 5 erasers.

Step-by-step explanation:

Since we have given that

Number of packages of pencil = 10

Number of packages of erasers = 6

We need to find the least number of pencil and erasers.

L.C.M of 10 and 6 = 30

So, the number of pencils would be

30÷ 10 = 3

The number of erasers would be

30 ÷ 6 = 5

Hence, there should be 3 pencils and 5 erasers.

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A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.

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