This is (y2-y1)/(x2-x1), y2 being 12, y1 being 7, x2 being -39 and x1 being 26. So if you plug in the points it would be: (12-7)/(-39-26). This solved equals: -5/65 which simplified equals: -1/13
If Andrew were to rest, he would not be moving (walking). During such a period, the beginning distance would be the same as the ending distance.
In this graph there are two such time intervals: BC and DE. Notice how the graph is 'flat' on each; this 'flat' graph indicates a speed of zero.
What is the mode and median of 1,2,1,3,3,5,3,4,5,4,3,2,5,3,1.
tankabanditka [31]
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u> </u></em><em><u>uh</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em>