9514 1404 393
Answer:
21.25 seconds
Step-by-step explanation:
In miles per second, the speed of the jet is ...
(720 mi/h)/(3600 s/h) = 1/5 mi/s
The speed of the sound is the same:
(1 mi)/(5 s) = 1/5 mi/s
Then the rate of closure between the airplane and the sound is ...
(1/5 mi/s) +(1/5 mi/s) = 2/5 mi/s
To find the time required to close a gap of 8 1/2 miles, we can use the relation ...
time = distance/speed
time = (8.5 mi)/(0.4 mi/s) = 21.25 s
The pilot will hear the thunder 21.25 seconds after the flash.
Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus
Ksivusya [100]
Given:
The given equation is:
To find:
The value of p.
Solution:
We have,
Multiply both sides by 3.
Isolating the variable terms, we get
Divide both sides by 11, we get
Therefore, the required solution is 
.
Answer:
14
Step-by-step explanation:
Perimeter= 99
XV+VW+WX=99
4z+3z+1+z+2=99
8z+3=99
8z= 96
z=96/8
z= 12
WX= z+2= 12+2= 14.
Hope it helps :-)
Since triangle BDE is right, we can check it for special rules: BD is hypotenuse = 20, and BE = 12, both divisible by 4: get 5 and 3... so it's a 3-4-5 special right triangle, the 4×4 = 16 m for side DE.
Since AD bisects angle A, I think then side DG should be congruent with DG. So then
DG = 16 m
Answer:
D. X= -100
Step-by-step explanation:
5×x/5=5×(-20) (reduce and multiply)
X= -100
