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Nataly_w [17]
3 years ago
15

Write the following as an inequality.

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

  -2 < w ≤ 6

Step-by-step explanation:

The inequalities you're asked to combine are ...

  -2 < w

  6 ≥ w

Turn one of these around so the "arrows" point in the same direction. (My preference is that they point to the left.) Now you have ...

  -2 < w

  w ≤ 6

You combine these by putting w in the middle:

  -2 < w ≤ 6

_____

<em>Alternate solution</em>

I like the above solution because it puts the components of the expression in the same (left-right) order as they appear on a number line. However, both inequalities can be turned around to get ...

  6 ≥ w > -2

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PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the
stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

  • A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

  • B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0  True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

  • C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4  True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

  • D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10)  is not one of the vertices of the shaded region of the  set of inequalities.

3 0
3 years ago
$10,000 for 20 years at 5% compounded annually
saveliy_v [14]

Answer:

$26532.98

Step-by-step explanation:

<u>Given:</u>

  • Principal = $10000
  • Profit rate = 5% PA compounded
  • Time = 20 years
  • Compounds = 20*1 = 20

<u>Sum is:</u>

  • 10000*(1 + 5/100)²⁰ ≈ 26532.98
3 0
3 years ago
If the graph of a quadratic does not intercept the x axis at any point, then it has:
katrin [286]

Answer:

No real roots

Step-by-step explanation:

Roots of a quadratic are the x-intercepts of the graph

3 0
3 years ago
Algebra Find the values for x and y in parallelogram ABCD. AE= 2x, EC=y+4, DE=x, EB=2y-1. AC and BD intersect at point E
erastova [34]

Answer:

x

=

y

=

A

E

=

2

x

=

E

C

=

y

+

4

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D

E

=

x

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6 0
3 years ago
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
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