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Igoryamba
3 years ago
15

What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

5(2)5(3)
Mathematics
2 answers:
butalik [34]3 years ago
5 0

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

kogti [31]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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<em>Comment on the question</em>

Since this answer is not among the answer choices, I suggest you ask your teacher to demonstrate how this problem is worked.

It appears as though the answers go with the problem 18x^9 +30x^6. Maybe there's a typo somewhere. For that problem, the best choice is the 2nd answer.

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