What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

Question

3 years ago

15

5(2)5(3)

2 answers:

butalik [34] · Answer 1 · 2022-01-21T07:14:17+03:00

ANSWER

$10C_5(2)^{5}( - 3)^5$

EXPLANATION

The given binomial expansion is:

${(2x - 3y)}^{10}$

Compare this to

${(a + b)}^{n}$

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

${x}^{5} {y}^{5}$

This implies that, r=5.

The terms in the expansion can be obtained using

$T_{r+1}=nC_ra^{n-r}b^r$

We substitute the given values to obtain;

$T_{5+1}=10C_5(2x)^{10-5}( - 3y)^5$

$T_{6}=10C_5(2x)^{5}(3y)^5$

$T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5} {y}^{5}$

Hence the coefficient is;

$10C_5(2)^{5}( - 3)^5$

kogti [31] · Answer 2 · 2022-01-21T09:05:27+03:00

kogti [31]3 years ago

3 0

Answer:

B

Step-by-step explanation: