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3 years ago

What's the answer ?????

Mathematics

1 answer:

Strike441 [17]3 years ago

3 0

Tommy waited at a red light.
hence why the line does not move.

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Rationalise the denominator by 6 root 7 minus 1

nikklg [1K]

Answer:

Assuming the numerator was 1.

$(6\sqrt{7}+1)/251$

Step-by-step explanation:

Assuming the numerator was 1.

$1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251$

7 0

3 years ago

Is 4:12 equivalent to 5:15

vlabodo [156]

Answer:

Yes.

Step-by-step explanation:

Ratios also function as fractions.

4/12 = 1/3 = 0.333

5/15 = 1/3 = 0.333

4 0

2 years ago

. Which ordered pairs in the form (x, y) are solutions to the equation 7x – 5y = 28?

Brut [27]

we know that

If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation

we have the equation

$7x-5y=28$

Let's verify all the cases to determine the solution to the problem.

case A) point $(-6,-14)$

Substitute the values of x and y in the equation

$x=-6\\y=-14$

$7(-6)-5(-14)=28$

$-42+70=28$

$28=28$ -------> is true

therefore

The point $(-6,-14)$ is a solution of the equation

case B) point $(-1,-7)$

Substitute the values of x and y in the equation

$x=-1\\y=-7$

$7(-1)-5(-7)=28$

$-7+35=28$

$28=28$ -------> is true

therefore

The point $(-1,-7)$ is a solution of the equation

case C) point $(4,10)$

Substitute the values of x and y in the equation

$x=4\\y=10$

$7(4)-5(10)=28$

$28-50=28$

$-22=28$ -------> is not true

therefore

The point $(4,10)$ is not a solution of the equation

case D) point $(7,9)$

Substitute the values of x and y in the equation

$x=7\\y=9$

$7(7)-5(9)=28$

$49-45=28$

$4=28$ -------> is not true

therefore

The point $(7,9)$ is not a solution of the equation

therefore

the answer is

$(-6,-14)$

$(-1,-7)$

8 0

3 years ago

Read 2 more answers

Estimate the product of 67 an 73 round each number to the neares tenes

vampirchik [111]

Answer:

4900

Step-by-step explanation:

73*67

70*70

7*7(10^2)

49(100)

4900

6 0

3 years ago

Read 2 more answers

Carbon-14 has a half-life of 5,730 years. If a sample contained 70 mg originally, how much is left after 17,190 years?

kow [346]

17,190 / 5,730 = 3. This means we must divide 70mg in half 3 times

70 / 2 = 35

35 / 2 = 17.5

17.5 / 2 = 8.75

There will be 8.75 mg left after 17,190 years.

7 0

3 years ago