Answer please this is my last try.
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The unit tangent vector is T(u) and the unit normal vector is N(t) if the vector function. R(t) is equal to 9 2 t, e9t, e−9t.
<h3>What is vector?</h3>It is defined as the quantity that has magnitude as well as direction also the vector always follows the sum triangle law.
We have vectored function:
Find its derivative:
Now its magnitude:
After simplifying:
Now the unit tangent is:
After dividing and simplifying, we get:
Now, finding the derivative of T(u), we get:
Now finding its magnitude:
After simplifying, we get:
Now for the normal vector:
Divide T'(u) and |T'(u)|
We get:
Thus, the unit tangent vector is T(u) and the unit normal vector is N(t) if the vector function. R(t) is equal to 9 2 t, e9t, e−9t.
Learn more about the vector here:
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