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pentagon [3]
3 years ago
5

Help please on 3 and 4

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

In (3) we're supposed to multiply both sides by 7/4 but the 7/4 got flipped over on the right hand side.

In (4) we lost a minus sign going from the second to third step.  We would have been better off multiplying both sides by -6.


Oksi-84 [34.3K]3 years ago
7 0

Hi,

For 3:

Instead of multiplying right hand side with 7/4, it was done with 4/7.

So, correct solution would be:

\left(\dfrac{7}{4}\right)\dfrac{4}{7}m=\dfrac{7}{4}22\Rightarrow m=\dfrac{7\cdot 11}{2}=\dfrac{77}2.

For 4: on the left hand side, instead of n, correct value is --n,

then --n = 18 |·(--1) ⇒ n = --18.

Have you understood ?

Green eyes.

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