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3 years ago

Problem Solving

Mathematics

1 answer:

Umnica [9.8K]3 years ago

8 0

November(350,489), October(350,080), then December(305,939)

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Equation of a line that has a slope of -2 and passes through the point (-1,4)

EleoNora [17]

Answer:

y=mx+b

Step-by-step explanation:

thats the formula i think

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3 years ago

Eureka Math : 5 ÷ 1/3= ____. There are ___ thirds in 1 whole. There are ___ thirds in 5 wholes. If 5 is 1/3, what is the whole?

oksian1 [2.3K]

Let me edit your question to simplify it.

Eureka Math :

A)5 ÷ 1/3= ____.

B) There are ___ thirds in 1 whole.

C) There are ___ thirds in 5 wholes.

D) If 5 of 1/3, what is the whole? ___

E) 3 ÷1/5= ____ .

F) There are ___ fifths in 1 whole.

G) There are ___ fifths in 3 wholes.

H) If 3 of 1/5, what is the whole?___

Answer:

A) 15

B) three thirds

C) 15 wholes

D) whole is 2

E) 15

F) five fifths

G) 15 fifths

H) whole is 1

Step-by-step explanation:

$5$ ÷ $\frac{1}{3} =5*\frac{3}{1}$

$5$ ÷ $\frac{1}{3}=15$

Third:

third means $\frac{1}{3}$

To make 1 whole from thirds, we need three thirds i.e. $\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1\ Whole$

In 1 whole there are three thirds, so in 5 wholes there are $5*3=15$ wholes.

In $5\ of\ \frac{1}{3}=5*\frac{1}{3} =\frac{5}{3}$

$\frac{5}{3}=1.6$

The whole of $1.6$ or $\frac{5}{3}$ is 2 (rounding 1.6 to 2)

$3$ ÷ $\frac{1}{5}=3*5=15$

Fifth: means $\frac{1}{5}$

To make 1 whole of fifths we need five fifths i.e. $\frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5}=\frac{1+1+1+1+1}{5}=\frac{5}{5}=1$

In 1 whole we have 5 fifths, so in 3 wholes we have $3*5=15$ fifths

$3\ of\ \frac{1}{5}=3*\frac{1}{5}=\frac{3}{5}=0.6$

rounding 0.6 equals to 1

thus whole is 1.

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3 years ago

Write a system of equation

JulsSmile [24]

Answer:

In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought. An equation system is usually classified in the same manner as single equations, namely as a: ... System of difference equations

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3 years ago

Suppose that the domain of the propositional function P(x) consists of –5, –3, –1, 1, 3, and 5. Express ∀x((x ≠ 1) → P(x)) witho

Crazy boy [7]

Answer:

The Answer and explanation with steps in the following attachment

Step-by-step explanation:

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3 years ago

Choose an equivalent ratio. 4:9 A) 27:40 B) 27:18 C) 12:27 D) 16:27

jek_recluse [69]

Answer:

The answer is C.

Step-by-step explanation:

The answer is C because both numbers in 4:9 can be multiplied by the same factor (3) to get 12:27, the answer. No other choice works because they require two different number factors, not just one, which means they aren't equivalent ratios to 4:9.

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3 years ago