Question

Help! Quick please!

Answer 1

B..............
c>=3 and n<0 and p<=(9-3 c)/n

Answer 2

Answer:

n ≥ − the quantity 3 times c minus 9 all over p

Step-by-step explanation:

To solve inequalities you should use the same method as to solve equalities.

1. First write down the inequality:

$-np-6\leq 3(c-5)$

2. Solve the parentheses:

$-np-6\leq 3c-15$

3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:

$-np\leq 3c-15+6\\\\-np\leq 3c-9$

4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:

$n\geq -(\frac{3c-9}{p})$