Answer:
1st
Vertex
we have
f(x)=x²-18x+88
let
y=x²-18x+88
comparing above equation with ax²+bx+c
we get
a=1
b=-18
c=88
now
vertex(x,y)=(-b/2a,f(-b/2a))
x=(18/2×1)=9
y=f(9)=9²-18×9+88=7
SO
VERTEX(X,Y)=(9,7)
=
Whole, integer, and rational
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>Approximate the value of </em>
<em> to the nearest tenths place. Plot the approximation on the number line.</em>
(Please have a look at the attached photo)
My answer:
The value nearest tenths place of is: 3.3
Hope it will find you well.
Answer:
The center is at (0,0)
The vertices are at ( (
±2 sqrt(2),0)
foci are (
±sqrt(5),0)
Step-by-step explanation:
3x^2 + 8y^2 = 24
Divide each side by 24
3x^2 /24 + 8y^2/24 = 24/24
x^2/8 + y^2 /3 = 1
The general equation of an ellipse is
(x-h)^2/ a^2 + (y-k)^2 / b^2 = 1
a>b (h,k) is the center
the coordinates of the vertices are (
±a,0)
the coordinates of the foci are (
±c,0), where ^c2=a^2−b^
2
The center is at (0,0)
a = sqrt(8) = 2sqrt(2)
The vertices are at ( (
±2 sqrt(2),0)
c = 8 - 3 =5
foci are (
±sqrt(5),0)
Your answer would be 3.4
Anything under 5 it stays the same and anything over 5 it goes up one
