Question

Solve for x in the following equation.

Answer 1

For this case we must solve the following equation of the second degree:

$x ^ 2 + 4x = 32\\x ^ 2 + 4x-32 = 0$

The solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = 4\\c = -32$

Substituting:

$x = \frac {-4 \pm \sqrt {4 ^ 2-4 (1) (- 32)}} {2 (1)}$

$x = \frac{-4\pm\sqrt{16+128}}{2}$

$x = \frac {-4 \pm \sqrt {144)}} {2}$

$x = \frac {-4 \pm12} {2}$

So:

$x_ {1} = \frac {-4 + 12} {2} = \frac {8} {2} = 4\\x_ {2} = \frac {-4-12} {2} = \frac {-16} {2} = - 8$

Answer:

$x_ {1} = 4\\x_ {2} = - 8$

Answer 2

Answer to this equation:

B. x=4;-8

You can use an online calculator or just a calculator for this. :)