Answer:
The magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N
Explanation:
Given;
distance of separation of the two wires, d = 18 cm
current in the first wire, I₁ = 8 A
current in the second wire, I₂ = 26 A
length of the wire, L = 2.1 m
permittivity of free space, μ₀ = 4π x 10⁻⁷ N·m/A = 1.257 × 10⁻⁶ N·m/A
The magnitude of the magnetic force on the wire carrying greater current is given as;
Therefore, the magnitude of the magnetic force on the wire carrying greater current is is 4.85 x 10⁻⁴ N
Answer:
27.34 (no unit)
Explanation:
26.975*82.33%+29.018*17.67%
=27.34
Answer:
α = 3.59 [rad/s^2]]
Explanation:
First we have to convert the values of the angular speeds of revolutions per minute to radians on second.
wf = final angular velocity = 460 [rpm]
wo= initial velocity = 48 [rpm]
t = time = 12 [s]
now we can replace, in the following equation:
Answer
b. energy
Explanation:
wave is a disturbance that carries energy from one particle to another particle.