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Scilla [17]
3 years ago
13

You buy a new computer for $1,500. The value of the computer decreases by 6%

Mathematics
2 answers:
bija089 [108]3 years ago
6 0

Answer:

Hey there!

Each year, the computer is (100-6), or 94% of it's original value.

Thus, we have:

Original: 1500

First year: 1500(0.94)

Second year: 1500(0.94)(0.94)

Third year: 1500(0.94)(0.94)(0.94)

Fourth year: 1500(0.94)(0.94)(0.94)(0.94)

Fourth year: 1171 dollars.

Hope this helps :)

Naya [18.7K]3 years ago
5 0

Answer:

$1171.05

Step-by-step explanation:

1500 × (1-(6 / 100))⁴

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Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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With 5 shoots, the probability of making at least one is \frac{211}{243}, hence the probability of making none, P(X = 0), is \frac{232}{243}, hence:

(1 - p)^5 = \frac{232}{243}

\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

P(X \geq 2) = 1 - P(X < 2)

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461

P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527

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P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

More can be learned about the binomial distribution at brainly.com/question/24863377

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Answer:

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