Answer:
see below
Step-by-step explanation:
It is generally convenient to start at the y-intercept and use the slope to count squares for rise and run.
<u>First equation</u>
The y-intercept is -3. The ratio of rise to run is 1/4, so the dashed line will go up 1 square for each 4 squares to the right. To the left, it will go down 1 square for each 4 squares to the left. Since the inequality is y > ( ), the shading will be <em>above</em> the (dashed) line.
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<em>Second equation</em>
The y-intercept is 0. The ratio of rise to run is -1/2, so the solid line will go down 1 square for each 2 squares to the right. To the left, it will go down 1 square for each 2 squares to the left. Since the inequality is y ≥ ( ), the shading will be <em>above</em> the (solid) line.
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<em>Comment on accurate drawing</em>
For good accuracy, it is usually convenient to draw the boundary lines between points close to the edge of the graph. The first equation is a little tough that way because there aren't two sets of 4 squares between the y-axis and the edge of the graph.