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wariber [46]
3 years ago
12

Use the quadratic formula to solve the equation 2x^2+2x-4=0

Mathematics
1 answer:
const2013 [10]3 years ago
4 0

Answer:

<h2>x = -2 or x = 1</h2>

Step-by-step explanation:

The quadratic formula for the quadratic equation ax² + bx + c = 0:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

2x^2+2x-4=0\qquad\text{divide both sides by 2}\\\\x^2+x-2=0

a=1,\ b=1,\ c=-2

Substitute:

x=\dfrac{-1\pm\sqrt{1^2-4(1)(-2)}}{2(1)}=\dfrac{-1\pm\sqrt{9}}{2}=\dfrac{-1\pm3}{2}\\\\x_1=\dfrac{-1-3}{2}=\dfrac{-4}{2}=-2\\\\x_2=\dfrac{-1+3}{2}=\dfrac{2}{2}=1

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Need help can someone plz help me solved this problem ASAP! Need help I will mark you as brainiest
erik [133]

Answer: 22, 38

               3, 7

               8, 12

<u>Step-by-step explanation:</u>

It is given that the PERIMETER is BETWEEN 22 and 38

-->          22 < P < 38

Perimeter = 2w + 2L

It is given that L = w + 5

Substitute P with 2w + 2L and substitute L with w + 5

                22 <  2w + 2(w + 5) < 38

                 22 < 2w + 2w + 10 < 38    

                  12 <          4w        < 28    

-->               3 <          w          < 7          

Since L = w + 5, then w = L - 5

Substitute P with 2w + 2L and substitute w with L - 5

                22 <  2(L - 5) + 2L < 38

                 22 < 2L + 2L - 10 < 38    

                 32 <          4L        < 48    

-->               8 <            L        < 12  

7 0
3 years ago
-6x^2-5x-5=<br> −6x <br> 2<br> −5x−5=<br> \,\,-4x^2<br> −4x <br> 2
aev [14]

Answer:

what is the question? it's not clear

3 0
3 years ago
Find the value of x when 6-4x = 6x-8x-2.
mestny [16]

Answer:

4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6−4x=6x−8x−2

6+−4x=6x+−8x+−2

−4x+6=(6x+−8x)+(−2)(Combine Like Terms)

−4x+6=−2x+−2

−4x+6=−2x−2

Step 2: Add 2x to both sides.

−4x+6+2x=−2x−2+2x

−2x+6=−2

Step 3: Subtract 6 from both sides.

−2x+6−6=−2−6

−2x=−8

Step 4: Divide both sides by -2.

−2x−2=−8−2

x=4

here is a link:

https://www.mathpapa.com/algebra-calculator.html?q=6-4x%3D6x-8x-2.

6 0
4 years ago
Area of rectangle with diagonal of 5 in but length not given
sergij07 [2.7K]

Draw a rectangle with diagonal 5 in. Inside this rect. are 2 acute triangles of hypotenuse 5. Note that 3^2 + 4^2 = 5^2; thus the width of the rect. is 3 and the length is 4, with the result that the hypo. is sqrt(3^2+4^2), as expected.




3 0
3 years ago
write an equation for the line that passes through the point (8,3) and parallel to -4x+8y=23. Use slope-intercept form.
kvasek [131]
(1/2)x+b=y because the equation that given the slope is 1/2 if you leave y alone and take the x’s number

put the point now , 4+b=3 so b is -1

the equation is (1/2)x-1=y
6 0
3 years ago
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