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3 years ago

Where are the Holy Lands located? Why is this area so important to 3 major religions?

2 answers:

8 0

The Holy Land refers to the area located between the Mediterranean Sea and the Jordan River, especially the area surrounding Jerusalem.<span>

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nekit [7.7K]3 years ago

6 0

It is located in Wisconsin, I don't know the second question

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For Triangle PQM, where M is the Right Angle and PQ is the Hypotenuse. You know side PM = 8, side PQ = 17, Side MQ = 15. Find An

Sergeeva-Olga [200]

Answer:

61.9°

Step-by-step explanation:

tan p = opposite/ adjacent

tan p = 15/8

$tan^{-1}$ (15/8)

4 0

3 years ago

Help me i'll help you back

Dmitriy789 [7]

Answer:

A, C, B, respectively

Step-by-step explanation:

science(density and buoyancy)

8 0

3 years ago

Find the perimeter of the triangle .

lawyer [7]

Answer:

P = 9x + 22

Step-by-step explanation:

Perimeter = sum of all sides

P = (3x + 11) + (3x + 11) + (3x)

P = 9x + 22

I hope this helps! God bless

5 0

2 years ago

Use the grouping method to factor the polynomial below completely.

Otrada [13]

After factor simplification of the polynomial, The answer is D

6 0

3 years ago

Read 2 more answers

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

3 years ago