Question

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Answer 1

Answer by JKismyhusbandbae: -12 ≤ f ≤ 6

-3f - 9|-8+8 ≤ 19 + 8

|-3f-9|≤ 27

-3f-9≤ 27 and -3f - 9≥ 27

-3f-9+9≤27+9

-3f ≤ 36

(-3f) (-1) ≥ 36 (-1)3f ≥ - 36

$\frac{3f}{3}$ ≥ $\frac{-36}{3}$

f ≥ - 12-3f

-9+9≥-27+9

-3f≥-18

$\frac{3f}{3}$ ≤ $\frac{18}{3}$

F  ≤ 6

Answer 2

Remark

Just as an aside, we would answer this if only 10 points were offered.

| - 3f - 9 | - 8 ≤ 19                  Add 8 to both sides.

| - 3f - 9 | - 8 + 8 ≤ 19 + 8

| - 3f - 9 | ≤ 27

First Solution

- 3f - 9 ≤ 27                  Add 9 to both sides

- 3f - 9 + 9 ≤ 27 + 9     Combine the terms on the left

- 3f ≤ 36                       Divide by - 3. Be careful about handling the ≤ sign

f ≥ 36/-3                       Do the division

f ≥  - 12

Second Solution

- 3f - 9 ≥ - 27   Add 9 to both sides.              

-3f - 9 + 9 ≥ - 27 + 9

- 3f ≥ - 18

f ≤ - 18/-3

f ≤ 6

The solution set to this is the set of values between 6 and - 12

6 ≥ f  and f ≥ - 12   <<<<<< Answer