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3 years ago

Reduce the fraction to lowest terms. Do not use spaces in your answer. 5r-5s/5r+5s=

Mathematics

2 answers:

ruslelena [56]3 years ago

8 0

Your answer is r-s/r+s!
I hope this helps!!!

Misha Larkins [42]3 years ago

8 0

Answer: The reduced form of the given fraction is

$\dfrac{r-s}{r+s}.$

Step-by-step explanation: We are given to reduce the following fraction to lowest terms:

$F=\dfrac{5r-5s}{5r+5s}~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To reduce a fraction to its lowest terms, we need to find the common factors in both the numerator and denominator and they should be cancelled.

From equation (i), we get

$F\\\\\\=\dfrac{5r-5s}{5r+5s}\\\\\\=\dfrac{5(r-s)}{5(r+s)}\\\\\\=\dfrac{r-s}{r+s}.$

Thus, the reduced form of the given fraction is

$\dfrac{r-s}{r+s}.$

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A sixth-grade student bought three cans of tennis balls for $4 each. Sales tax for all three cans was $.95. Write an expression

Oksanka [162]

(3*4)+.95=x
12+.95=x
12.95=x

3 0

4 years ago

Two companies are competing for a contract to sell the school wifi. Comporium

enot [183]

It would take 8 months for Comporium to cost more than Brighthouse.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let c represent the total cost to install Wi-Fi for m number of months.

For Comporium:

c = 39.99m + 100

For Brighthouse:

c = 49.99m + 20

For Comporium to cost more than Brighthouse:

39.99m + 100 > 49.99m + 20

10m > 80

m > 8

It would take 8 months for Comporium to cost more than Brighthouse.

Find out more on linear equation at: brainly.com/question/14323743

6 0

2 years ago

8 = y + 3 solve for the variable

Dominik [7]

$8 = y + 3 \\ - 3 - 3 \\ 5 \\ y = 5$

6 0

3 years ago

Read 2 more answers

the intake pipe can fill a certain tank in 6 hours when the outlet pipe is closed, but with the outlet pipe open it takes 9 hour

Leona [35]

The outlet pipe will take 18 hours to empty the tank.

St<u>ep-by-step explanation:</u>

Number of hours taken by inlet pipe to fill the tank=6

work done by the inlet pipe in 1 hour=1/6

Number of hours taken by the inlet pipe to fill the tank with the outlet pipe open=9

work done by the inlet pipe in 1 hour with outlet pipe open=1/9

we have to determine the time taken by the outlet pipe to empty the tank

The inlet and outlet pipe does the opposite work.

$\\time\ taken\ by\ the\ outlet\ pipe\ to\ empty\ the\ tank=x\\work\ done\ by\ the\ outlet\ pipe\ in\ 1\ hour=1/x\\(1/6-1/x)9=1\\1/6-1/x=1/9\\1/x=1/6-1/9=3/54\\x=54/3=18$

The outlet pipe takes 18 hours to empty the tank.

6 0

3 years ago

Plslslsllslslslslslalalalsllsls helpppppp

dybincka [34]

Answer:

You use the trigonometric ratio (see below for explanation & answer)

Step-by-step explanation:

$tan(50)=\frac{630}{d}$

$d=\frac{630}{tan(50)}$

$d= 528.6$

So, 528.6 is your answer. Have a great day! Hope I helped!

3 0

3 years ago