Ask question

Ask question

All categories

3 years ago

12

Which property does the statement illustrate? Column A Column B 1. (p + 3) + q = p + (3 + q) 2. 8 + (9 + 4) = (8 + 9) + 4 3. 4(x

– 2) = 4x – 8 4. 7(3 + 5) = 7 • 3 + 7 • 5 A. associative property of addition B. distributive property Question

2 answers:

igomit [66]3 years ago

6 0

The answer is associative property

Katyanochek1 [597]3 years ago

6 0

Associative property of
<span>addition</span>

You might be interested in

I need sum help please and thanks :)

Leona [35]

Answer:

6/16n is your answer I think

4 0

3 years ago

Graph the solution of the inequality: 3/7 (35x-14) ≤ 21x/2 + 3

hammer [34]

Hello there!

In order to graph the solution, we need to solve it first.

So let's start....

3/7(35x - 14) ≤ 21x/2 + 3

15x -6 ≤ 21x/2 + 3

15x - 21x/2 ≤ 3 + 6

9x/2 ≤ 9

x ≤ 9* 2/9

x ≤ 18/9

x ≤ 2

See the picture for the graph

Please let me know if you have questions about the answer.

Thanks!

5 0

3 years ago

Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $115, and 33 tickets w

strojnjashka [21]

3 x 25 =75 and then 5 x 8 =40 and you would just add 75 and 40 which is where you would get 115. So the answer would be D 25 child 8 adult
Hope this helps! :)

6 0

3 years ago

45-45-90 method <br> Please help and show your work!!!

Dvinal [7]

Answer:

hope this helps and u understood it

check the steps in the picture attached

3 0

2 years ago

Ursula and Velda live 4 km apart. They leave their homes at the same time, walking towards each other. If Ursula walks at a rate

vladimir2022 [97]

Answer: 250 m

Step-by-step explanation:

Given

Distance between Ursula and Velda house is 4 km or 4000 m

Ursula walks at the rate of $400\ m/h\ or\ \frac{20}{3}\ m/min$

Velda walks at the rate of $600\ m/h\ or\ 10\ m/min$

Time taken by them to cover 4000 m is

$\Rightarrow \dfrac{4000}{400+600}=4\ h\ or\ 240\ min$

Distance covered by them 15 min before they meet

Ursula $=\frac{20}{3}\times 225=1500\ m$

Velda $=10\times 225=2250\ m$

The total length covered by them is $=1500+2250=3750\ m$

They are $4000-3750=250\ m$ apart before they meet

6 0

2 years ago