We use the BODMAS method to solve the given questions.
Solve the Bracket then Divide Multiply Add and Subtract
1. 32÷4×(16×1/2) - 2
= 32÷4 × ( 8 ) - 2
= 8 × 8 - 2 = 64 - 2 = 62
2. 20 ÷ (5×2/5) + 3
= 20 ÷ (2) + 3 = 20 ÷ 2 + 3
= 10 + 3 = 13
3. 1/2 ×(6×4) ÷ 3 + 2
= 1/2 × 24 ÷ 3 + 2
= 1/2 × 8 + 2
= 4 + 2 = 6
4. 2 (6÷2+8) - 4
= 2 (3+8) - 4
= 2 × 11 - 4
= 22 - 4
= 18
Answer:
x = 3.6
Step-by-step explanation:
If 2 chords of a circle intersect then the product of the parts of one chord is equal to the product of the parts of the other chord, that is
5x = 6 × 3 = 18 ( divide both sides by 5 )
x = 3.6
Answer:
a = 6.7m is the answer.
Step-by-step explanation:
a = ?
b = 6m
c = 9m
According to the Pythagorean theorem,
a² + b² = c²
a² + 6² = 9²
a² + 36 = 81
a² = 81 - 36
a² = 45
a = 6.708
round to the nearest tenth,
a = 6.7m
∴ Janice is 6.7m high up in the air.
Answer:
The team lost 13 yards
Step-by-step explanation:
They lose 20 then gain 7. so the equation would be 20-7=13
Answer:
Step-by-step explanation:
![(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3} \\\\= 7 + \sqrt{3} + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7B3%7D%20%2B4%29%281%2B%5Csqrt%7B3%7D%29%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%281%2B%5Csqrt%7B3%7D%20%29%2B4%281%2B%5Csqrt%7B3%7D%29%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%20%2B%20%28%5Csqrt%7B3%7D%20%29%5E2%20%2B%204%20%2B%204%5Csqrt%7B3%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%20%2B%203%2B4%2B4%5Csqrt%7B3%7D%20%20%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%20%20%2B%204%5Csqrt%7B3%7D%20%5C%5C%5C%5CTake%20%5C%20%5Csqrt%7B3%7D%20%5C%20common%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%20%281%2B4%29%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%285%29%5C%5C%5C%5C%3D%207%20%2B%205%5Csqrt%7B3%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
