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VashaNatasha [74]
3 years ago
15

What number do you use to divide 180 by to get 1.8

Mathematics
2 answers:
aliina [53]3 years ago
7 0
You have to divide 180 by 90.5 to get 1.8

Natalija [7]3 years ago
3 0
You use 100 to get 1.8
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Please help with these 4 questions
horsena [70]

We use the BODMAS method to solve the given questions.

Solve the Bracket then Divide Multiply Add and Subtract

1. 32÷4×(16×1/2) - 2

= 32÷4 × ( 8 ) - 2

= 8 × 8 - 2 = 64 - 2 = 62

2. 20 ÷ (5×2/5) + 3

= 20 ÷ (2) + 3 = 20 ÷ 2 + 3

= 10 + 3 = 13

3. 1/2 ×(6×4) ÷ 3 + 2

= 1/2 × 24 ÷ 3 + 2

= 1/2 × 8 + 2

= 4 + 2 = 6

4. 2 (6÷2+8) - 4

= 2 (3+8) - 4

= 2 × 11 - 4

= 22 - 4

= 18

7 0
2 years ago
Find the value of x.
alex41 [277]

Answer:

x = 3.6

Step-by-step explanation:

If 2 chords of a circle intersect then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

5x = 6 × 3 = 18 ( divide both sides by 5 )

x = 3.6

6 0
2 years ago
Someone please help me answer this
vichka [17]

Answer:

a = 6.7m is the answer.

Step-by-step explanation:

a = ?

b = 6m

c = 9m

According to the Pythagorean theorem,

a² + b² = c²

a² + 6² = 9²

a² + 36 = 81

a² = 81 - 36

a² = 45

a = 6.708

round to the nearest tenth,

a = 6.7m

∴ Janice is 6.7m high up in the air.

7 0
3 years ago
Read 2 more answers
1. A team loses 20 yards and then they gain 7
Elena L [17]

Answer:

The team lost 13 yards

Step-by-step explanation:

They lose 20 then gain 7. so the equation would be 20-7=13

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B3%7D%2B4%5Cright%29%5Cleft%281%2B%5Csqrt%7B3%7D%5Cright%29" id="TexFormula
kirza4 [7]

Answer:

\huge\boxed{\sf 7 + 5\sqrt{3} }

Step-by-step explanation:

(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3}  \\\\= 7 + \sqrt{3}  + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
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