Answer:
3
HCF of 12, 45 and 75 by Prime Factorization
As visible, 12, 45 and 75 have only one common prime factor i.e. 3. Hence, the HCF of 12, 45 and 75 is 3.
Step-by-step explanation:
P(at least 5 rolls until 1) = P(4 rolls are not 1) = 5/6 x 5/6 x 5/6 x 5/6 = 0.4823 (4sf)
Fewer than 7 rolls to get second 1 after first takes 3 rolls means second occurs on 4th, 5th or 6th roll
The probability of each of these is 1/6, 5/6 x 1/6 and 5/6 x 5/6 x 1/6 respectively.
P(second 1 on 4th, 5th or 6th roll) = 1/6 + 5/36 + 25/216 = 91/216 = 0.4213 (4sf)
Answer:
The working is done in the image attached.
Answer:
I think 5
Step-by-step explanation:
