Answer:
5^6
Step-by-step explanation:
(5^3)^2
We know that a^b^c = a^(b*c)
5^(3*2)
5^6
Answer: B TRUST ME
I AM NOT IMPOSTER
Step-by-step explanation:
Answer: theres a answer key in the last slide & its 15 somehow...
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
2/5 = ?/10 = 0.4
2*(2/5) = (2*2)/(2*5) = 4/10
? = 4
