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GREYUIT [131]
3 years ago
6

Am I correct on #1???

Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

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I need answer pls, PLS
Dafna1 [17]

Answer:

The answer is 17

Step-by-step explanation:

First step is dividing 45÷9 = 5

Then, 2² = 4

Now you have: 4 × 5 - 3 => 20 - 3 => 17

3 0
3 years ago
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Which one is bigger 3.5km or 3,000 km
Alla [95]

Answer:

Converting kilometers to meters could never be simpler with our accurate length converter! ... Meters and kilometers both belong to the metric length scale, with these two units of measurement being on the larger side. ... 1 Kilometer equals 1000 Meters (1km = 1000m) ... 3 Kilometers equal 3000 Meters (3km = 3000m) ...

Step-by-step explanation:

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3 years ago
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What is the median of the data set? {50, 54, 62, 48, 49, 52}<br><br><br><br> plz help
Stella [2.4K]
Q1=49
Median=51
Q3=54

if i'm not wrong
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3 years ago
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Graph the line with slope 3/2 and y intercept -6
KiRa [710]

Answer:

y = 3 \div 2x - 6

Step-by-step explanation:

You do this by placing the graph on -6, then you go up 3/2.

4 0
3 years ago
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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
Sunny_sXe [5.5K]

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2} - x }{x(x - 3)(x + 3)}

Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 -  {x}^{2}  - x}{x( {x}^{2}  - 9)}

Collect like terms

\frac{ {x}^{2}  + 7x + 15 - 5}{x( {x}^{2}  - 9)}

Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

6 0
3 years ago
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