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stiv31 [10]
3 years ago
8

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

≈ 7.2

Step-by-step explanation:

Use distance formula:

d = √(8-4)² + (8-2)²

You might be interested in
heather has divided $6300 between two invesments, one paying 9%, the other paying 4%. If the return on her investment is $372, h
Ganezh [65]
Assuming that the two investments are  X & Y
X + Y = 6300
X = 6300 - Y                                       (1)

9/100X + 4/100 Y = 372                       (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400

I hope this is helpful 



6 0
3 years ago
The point A has co-ordinates (-4,6) and the point B has co-ordinates (7,-2).
Serhud [2]

Answer:

√185 or 13.60 units to the nearest hundredth.

Step-by-step explanation:

For the points (x1,y1) and (x2,y2) the length between the points is given by:

L = √ [ (x2-x1)^2 + (y2-y1)^]

So here we have:

Length of AB  √ [ (7- - 4)^2 + (-2 - 6)^2]

=  √ (121 + 64)

= √185.

3 0
2 years ago
Read 2 more answers
How do you use the distance formula and slope formula to find the lengths of a quadrilateral?
Natasha_Volkova [10]
The distance formula to find the length of the sides... opposite sides equal it could be a rectangle or parallelogram all sides equal, square or rhombus adjacent equal, kite and then the slope is used to check angles if the product of the 2 lines in -1 the lines are perpendicular (right angle) the slopes of 2 lines are the same the sides are parallel. Hope it helps.
5 0
3 years ago
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4
german

Answer:

range is  between 55.5 to 64.5

Step-by-step explanation:

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches

68% is 1 standard deviation from mean

To get the range of 1 standard deviation we add and subtract standard deviation from mean

mean = 60

standard deviation = 4.5

60 - 4.5= 55.5

60+4.5 = 64.5

1 standard deviation is between 55.5 to 64.5

That is 68% range is  between 55.5 to 64.5

8 0
3 years ago
What’s the gcf of 18k and 15k cubed?
Contact [7]

Answer:

The GCF for the variable part is  

k

Step-by-step explanation:

Since  

18

k

,

15

k

3

contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.

Steps to find the GCF for  

18

k

,

15

k

3

:

1. Find the GCF for the numerical part  

18

,

15

2. Find the GCF for the variable part  

k

1

,

k

3

3. Multiply the values together

Find the common factors for the numerical part:

18

,

15

The factors for  

18

are  

1

,

2

,

3

,

6

,

9

,

18

.

Tap for more steps...

1

,

2

,

3

,

6

,

9

,

18

The factors for  

15

are  

1

,

3

,

5

,

15

.

Tap for more steps...

1

,

3

,

5

,

15

List all the factors for  

18

,

15

to find the common factors.

18

:  

1

,

2

,

3

,

6

,

9

,

18

15

:  

1

,

3

,

5

,

15

The common factors for  

18

,

15

are  

1

,

3

.

1

,

3

The GCF for the numerical part is  

3

.

GCF

Numerical

=

3

Next, find the common factors for the variable part:

k

,

k

3

The factor for  

k

1

is  

k

itself.

k

The factors for  

k

3

are  

k

⋅

k

⋅

k

.

k

⋅

k

⋅

k

List all the factors for  

k

1

,

k

3

to find the common factors.

k

1

=

k

k

3

=

k

⋅

k

⋅

k

The common factor for the variables  

k

1

,

k

3

is  

k

.

k

The GCF for the variable part is  

k

.

GCF

Variable

=

k

Multiply the GCF of the numerical part  

3

and the GCF of the variable part  

k

.

3

k

3 0
3 years ago
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