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Rzqust [24]
3 years ago
15

Which absolute value function has a graph that is wider than the parent function, f(x) = |x|, and is translated to the right 2 u

nits?
Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

its c i just took the test

Step-by-step explanation:


Ipatiy [6.2K]3 years ago
5 0
Move to right c units means minus c from every x
wider means horizontal strech, means multiply every x by r where |r|>1

so
the new function would be
f(x)=r|x-2| where |r|>1
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Omar says that the least common multiple of 9 and 6 is 54. Which is true about Omar's statement?
Damm [24]

Hey there!

Let's pull out the multiples of each number and see which ones fall in line first.

9,18

6,12,18

The LCM is 18. Therefore, answer B and D are incorrect. A is incorrect because 9 * 6 is 54. Therefore, the answer is C.

I hope this helps!

5 0
3 years ago
Read 2 more answers
...................can someone plz help?
galben [10]

Answer:

2.5 feet

Step-by-step explanation:

65- 53 3/4 = 11.25

11.25= 2.5 per year

hope this helps!

8 0
4 years ago
Will mark as brainliest (must show work)
Sever21 [200]

Answer:

46

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW  then

m < XVY = m < YVW

      2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

      2x-x = 15-7, combine like terms

           x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY =  2x+7  = 2*8 +7 = 16 +7 = 23

m < YVW =  x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0
2 years ago
You are an assistant director of the alumni association at a local university. You attend a presentation given by the university
NNADVOKAT [17]

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

<h2> p1 -p2 ± z*\sqrt{((1-p1)*p1)/n1 + ((1-p2)*p2/n2}</h2>

0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = <u>0.102</u>

= 0.02 - 0.082 = <u>-0.062</u>

<u>There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>

<u></u>

<u>There is no significant difference between the two.</u>

5 0
3 years ago
(x +y)(x-y), ifx= -3, y=-5
Rufina [12.5K]

Answer:

-16

Step-by-step explanation:

(-3 + (-5))(-3 - (-5))

(-3 - 5)(-3 + 5)

(-8)*2

<u>-16</u>

5 0
3 years ago
Read 2 more answers
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