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Burka [1]
4 years ago
12

Write the following expression in terms of 2 and simplify 8V-64 Answer

Mathematics
1 answer:
Sholpan [36]4 years ago
5 0

Answer:

4V-32

If is was wrong then don't report on me just tell me and I will automatic fix it for you

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What is the GCF for 15 35 and 20
MArishka [77]

15 = 3 * 5

35 = 5 * 7

and 

20 = 2 * 2 * 5


so GCF = 5

8 0
3 years ago
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Solve the equation. Chec)<br> 5m - l = 4m + 5
rjkz [21]

Answer:

m=6

Step-by-step explanation:

3 0
3 years ago
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What is the area of this triangle?
Katen [24]
18.81
Half (6.6) base times height (5.7)
3 0
3 years ago
B) Your local shoe store anticipated giving away 2,500 pairs of shoes in one month, but they only sold 2,215 pairs of shoes. Wha
vampirchik [111]

Answer:

Approximate percent error = 15%

Step-by-Step Explanation:

Let the percentage of error be "e"

Anticipated sales = 2,500

Actual sales = 2,125

The percentage error "e" can be calculated as per the equation below:

2500*(1-e) = 2125

(1-e) = 2125/2500

1-e = 0.85

e = 1-0.85

e = 0.15

e = 15%

Approximate percentage error = 15%

6 0
3 years ago
The coordinates of the vertices of ∆PQR are P(-2,5), Q(-1,1), and R(7,3). Determine whether ∆PQR is a right triangle. Show your
Mashutka [201]

Given

∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

Determine whether ∆PQR is a right triangle

To proof

As given ∆PQR points are P(-2,5), Q(-1,1), and R(7,3)

First find out the sides of triangle

FORMULA

Distance formula between two points

D^{2}= (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}

 Distance   between two points P(-2,5) and Q(-1,1)

PR = \sqrt{(-1+2)^{2}+(1-5)^{2}  }

PR = \sqrt{17}

Distance between two points Q(-1,1)and  R(7,3)

QR = \sqrt{(7+1)^{2} +(3-1)^{2}  }

QR =\sqrt{68}

Distance between two points  R(7,3) and P(-2,5)

RP =\sqrt{(-2-7)^{2} + (5-3)^{2}  }

RP=\sqrt{85}

now show that ∆PQR is a right triangle

RP^{2} = PQ^{2} +QR^{2}

Putting the value given above

(\sqrt{85}) ^{2} = \sqrt{17} ^{2} +\sqrt{68} ^{2}

85 = 17 +68

85 =85

In the right triangle

HYPOTENUSE² = BASE² + PERPENDICULAR²

This is prove above

Hence ∆PQR is a right triangle

Hence proved










7 0
4 years ago
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