Write the following expression in terms of 2 and simplify 8V-64 Answer
1 answer:
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Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:
For those with defects <em>operating at a 6 sigma level, </em>the probability is:
Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:
Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.