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Bingel [31]
3 years ago
7

What is a real-world problem using ratios or rates that could be represented on a coordinate plane

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

Step-by-step explanation:

go to school

vova2212 [387]3 years ago
6 0

A real world promblem that uses ratios and raes that can be graphed on a corrdinate plane is a promblem that could possibly happen or has happened such has bank rupsie it doesnt all of a sudden happen it slowly decreases until you have no money left to pay your bills or have a home and that can be graphed if you are given the equation or numbers on how it happened

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How do I find the properties of a parabola
Elanso [62]
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3 0
4 years ago
Please answer the question below 15 points for answering!
Angelina_Jolie [31]
Take any 2 points from the given line and use the rule to find slope

(3,0) (0,-1)

Slope= y2-y1/x2-x1

Slope= -1-0/0-3= -1/-3 = 1/3

Final answer :

Slope = 1/3

So it’s the first option :)
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3 years ago
fred's auto sales purchases 3 new vehicles for $11,219, $31,611, and $18,204. what was the total cost for all the vehicles?
Anarel [89]
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8 0
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If 9 lbs.of pasta salad serves 15 people, how much pasta salad should you bring to a picnic with 76 people
goldenfox [79]

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7 0
3 years ago
Read 2 more answers
How can I find the complex roots of 125x^3+343. Please explain your steps
8_murik_8 [283]
First we assume that this is equal to zero

so what we notice is this is a sum of 2 perfect cube

recall that
a^3+b^3=(a+b)(a^2-ab+b^2)

125x^3+343=
(5x)³+(7)³=(5x+7)(25x²-35x+49)

now solve the part in second parenthasees because we can see that the first parenthasees (5x+7) is going to have a real root

remember quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
a=25
b=-35
c=49

x=\frac{-(-35)+/- \sqrt{(-35)^2-4(25)(49)} }{2(25)}
x=\frac{35+/- \sqrt{1225-4900} }{50}
x=\frac{35+/- \sqrt{-3675} }{50}
x=\frac{35+/- (\sqrt{3675})( \sqrt{-1}) }{50}
x=\frac{35+/- (\sqrt{3675})(i) }{50}
x=\frac{35+/- 35i\sqrt{3} }{50}
x=\frac{7+/- 7i\sqrt{3} }{10}

the comlex roots are

x=\frac{7+ 7i\sqrt{3} }{10} and \frac{7- 7i\sqrt{3} }{10}




3 0
4 years ago
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