4y+7x-3y+2x
(7x+2x)+(4y+-3y)
=9x+y
Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
mixas84 [53]
The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A
<h3>Algebra</h3>
2^x - 2
when x = 0
2^x - 2
= 2^0 - 2
= 1 - 2
= -1
when x = 1
2^x - 2
=2^1 - 2
= 2 - 2
= 0
when x = 2
2^x - 2
= 2^2 - 2
= 4 - 2
= 2
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The forces result in a right triangle. To obtain the resultant force, one can simply use the Pythagorean theorem. 1250 lbf and 2650 lbf both act as the legs of the triangle. Obtaining the hypotenuse via the theorem would yield the resultant force. This is done below:
c^2 = a^2 + b^2
c^2 = (1250)^2 + (2650)^2
c = 2930.017 lbf
Therefore, the magnitude of the resultant force is approximately equal to 2930 lbf.
Answer:
12/16 = 3/4
I divided both sides by 4.
Hope this helps!
-Mikayla
Answer:
Step-by-step explanation: i don’t know to be honest