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Ivahew [28]
4 years ago
14

which must be true of a quadratic function whose vertex is the same as its y-intercept? the axis of symmetry for the function is

x = 0. the axis of symmetry for the function is y = 0. the function has no x-intercepts. the function has 1 x-intercept.
Mathematics
2 answers:
Zina [86]4 years ago
8 0

Answer:

a. The axis of symmetry for the function is x = 0.

Step-by-step explanation:

edge 2020

Sholpan [36]4 years ago
5 0

If <u>quadratic function </u>y=ax^2+bx+c has <u>vertex </u>that is the same as its <u>y-intercept</u>, then

x_v=-\dfrac{b}{2a}=0,\\ \\b=0

and its equation is y=ax^2+c.

The graph of this quadratic function is translated graph of the function y=ax^2 up or down (depends on c).

This means  that there could be

  • two x-intercepts;
  • one x-intercept;
  • no x-intercepts.

The axis of symmetry of the graph of the function y=ax^2 is x=0 (y-axis).

Answer: correct choice is A

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4 years ago
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Can someone help me answer this? id really appreciate it
Angelina_Jolie [31]

Answer:

Step-by-step explanation:

n²+2 where n is number of small squares forming maximum corner square.

in step 1,n=1

step 2,n=2

step 3,n=3

step 4,n=4

when n=1

number of squares=1²+2=1+2=3

when n=2

total numbers=2^2+2=4+2=6

when n=3

total numbers=3²+2=9+2=11

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8 0
3 years ago
Please help 9/5a+12=5
vova2212 [387]
A = -35/9 is the answer
8 0
3 years ago
You are testing 0:=100 against :&lt;100 based on an SRS of 24 observations from a normal population. The data gives ¯=9 and =2.4
bekas [8.4K]

Answer:

-185.75297

Step-by-step explanation:

Solution:-

- We are testing whether the population mean u is equal to 100 as per claim.

                Null hypothesis: u = 100

- Where a alternate hypothesis suggest that the population mean ( u ) may be lower:

               Alternate hypothesis: u < 100

- We are given sample data parameters which are assumed to be normally distributed:

              sample mean, x_bar = 9

              sample standard deviation, s = 2.4

- A sample of n = 24 observation was taken from a population of ( N ) with unknown population standard deviation ( σ ).

- The conditions of standard normal distribution are no longer applicable i.e:

                 

              n = 24 < 30

              unknown population standard deviation ( σ )

- We will model the sample using t-distribution with ( n - 1 ) = 23 degrees of freedom.

- The t-statistics of the sample mean x_bar can be determined from standard t-distribution:

                 

                 t-test = \sqrt{n}* \frac{x_b_a_r - u}{s} \\\\t-test = \sqrt{24}* \frac{9 - 100}{2.4} \\\\t-test = -185.75297

- The t-test value for mean ( u ) is -185.75297

                         

                 

5 0
4 years ago
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