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Ivahew [28]
3 years ago
14

which must be true of a quadratic function whose vertex is the same as its y-intercept? the axis of symmetry for the function is

x = 0. the axis of symmetry for the function is y = 0. the function has no x-intercepts. the function has 1 x-intercept.
Mathematics
2 answers:
Zina [86]3 years ago
8 0

Answer:

a. The axis of symmetry for the function is x = 0.

Step-by-step explanation:

edge 2020

Sholpan [36]3 years ago
5 0

If <u>quadratic function </u>y=ax^2+bx+c has <u>vertex </u>that is the same as its <u>y-intercept</u>, then

x_v=-\dfrac{b}{2a}=0,\\ \\b=0

and its equation is y=ax^2+c.

The graph of this quadratic function is translated graph of the function y=ax^2 up or down (depends on c).

This means  that there could be

  • two x-intercepts;
  • one x-intercept;
  • no x-intercepts.

The axis of symmetry of the graph of the function y=ax^2 is x=0 (y-axis).

Answer: correct choice is A

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Iteru [2.4K]
Answer is C
Because 2 is your Y intercept and -1/2 means your going to move down 1 then move 2 to the right
7 0
2 years ago
Read 2 more answers
In the accompanying diagram of parallelogram ABCD,diagonals AC and DB intersect at E, AE = 3x - 4, andEC = x + 12.What is the va
skelet666 [1.2K]

x = 8

Explanation:

AE = 3x - 4

EC = x + 12

SInce diagonals AC and DB intersect at E

it means the lines which meet at the intersection E are equal. A and C meet at E which gives AE and EC

AE = EC

3x - 4 = x + 12

collect like terms:

3x - x = 12 + 4

2x = 16

divide both sides by 2:

2x/2 = 16/2

x = 8

4 0
1 year ago
PLZ HELP I WILL MARK AS BRAINLIEST
-Dominant- [34]

Answer:

  7 square units

Step-by-step explanation:

As with many geometry problems, there are several ways you can work this.

Label the lower left  and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.

The applicable formulas are ...

  area of a trapezoid: A = (1/2)(b1 +b2)h

  area of a triangle: A = (1/2)bh

So, our areas are ...

  AQRS = AWSQE - AWSR - AEQR

  = (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)

Factoring out 1/2, we have ...

  = (1/2)((2+5)·4 -2·2 -5·2)

  = (1/2)(28 -4 -10) = 7 . . . . square units

4 0
3 years ago
Solve x3 = 1 over 8. <br> 1 over 2 <br> ±1 over 2 <br> 1 over 4 <br> ±1 over 4
cricket20 [7]
X³ =  1/8

Take the cube root of both sides.

∛x³  = ∛(1/8)

Since x³ has 3 of such x multiplying each other so we bring out 1 of the x from the cube root sign as discussed.

x = ∛((1/2)*(1/2)*(1/2))

We bring out 1 of the (1/2) out of the cube root sign as well.

x = 1/2

So the answer is the first option.  1 over 2.

I hope this helps.
7 0
3 years ago
PLS HELP ME WITH THIS ALGEBRA!
artcher [175]

Answer:

  • 120 g

Step-by-step explanation:

A salt solution contains 10% salt and weights 80g.

<u>Salt content of the solution is:</u>

  • 80*0.1 = 8 g

<u>4% solution has 8 g salt, total solution is:</u>

  • 0.04x = 8
  • x = 8/0.04 = 200 g

<u>Water to be added:</u>

  • 200 - 80 = 120 g

6 0
3 years ago
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