The point-slope equation of the line is y-2=-2(x-7)
How will we find the equation of line?
First, we will find the slope of line using the given points then put slope and point in the formula to get equation of line.
We can find the equation as shown below:
Given points (6,4) and (7,2)
slope(m)= (2-4)/ (7-6)
m=-2/1
m=-2
The point slope form:
(y-y1) = m(x-x1)
y1=2, x1=7
putting in formula
(y-2) = -2(x-7)
y-2=-2(x-7)
Hence, the point-slope equation of the line is y-2=-2(x-7)
Learn more about straight lines here:
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If I read this right,
you put the numbers where the letters go
2 (8) (-4)
since they are in parenthesis, you multiply them.
= -64
Answer:
I don't know soorry. lalalala
Answer:
4091
Step-by-step explanation:
Given the equation;
3x + 7x − 28 + 31 − 8x
First, we would collect like terms;
3x + 7x − 8x − 28 + 31
Simplifying, we have;
For x = 2043;
2(2043) + 5 = 4086 + 5 = 4091.
Answer:
m∠CEH = 79°
Step-by-step explanation:
From the picture attached,
∠CED and ∠CEH are the pair of linear angles.
Since, pair of linear angles are supplementary angles.
m∠CED + m∠CEH = 180°
101° + m∠CEH = 180°
m∠CEH = 180° - 101°
= 79°
Therefore, measure of angle CEH is 79°.