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Gnoma [55]
3 years ago
12

Solve the equation. If you have one answer, type it in both boxes. If you have two answers, type your smallest answer in the fir

st box and your largest answer in the last box. |2x – 3| = 17
x =
Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

x = - 7 or x = 10

Step-by-step explanation:

The absolute value always returns a positive value, but the expression inside the bars can be positive or negative.

Given

| 2x - 3 | = 17, then

2x - 3 = 17 ( add 3 to both sides )

2x = 20 ( divide both sides by 2 )

x = 10

OR

- (2x - 3) = 17 ← distribute left side by - 1

- 2x + 3 = 17 ( subtract 3 from both sides )

- 2x = 14 ( divide both sides by - 2 )

x = - 7

As a check, substitute these values into the left side of the equation and if equal to the right side then they are the solutions

x = - 7 → | - 14 - 3 | = | - 17 | = 17 ← True

x = 10 → | 20 - 3 | = | 17 | = 17 ← True

Hence solutions are x = - 7 or x = 10

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A system of equations consists of a line s of the equation y = x – 5 and a line t that passes through the points (0, 2) and (8,
GenaCL600 [577]

Answer:

\text{The slope of the line t:}\ m=-\dfrac{3}{4}\\\\\text{The y-intercept of the line t:}\ b=2\\\\\text{The equation of a line t in the slope-intercept form:}\ y=-\dfrac{3}{4}x+2

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept → (0, b)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (8, -4) and (0, 2) → b = 2.

Calculate the slope:

m=\dfrac{2-(-4)}{0-8}=\dfrac{6}{-8}=-\dfrac{3}{4}

Therefore the equation of a line t in the slope-intercept form is:

y=-\dfrac{3}{4}x+2

5 0
3 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
4 years ago
Mari has a part time job. She earns $6 an hour. She makes at most $207.00 a week. What is the greatest number of hours that she
sergejj [24]

Answer:

If Mary earns 7$ an hour, we need to multiplicate 7$ by the number of hours worked for the entire week so we can get the salary per week.

Step-by-step explanation:

it's correct

8 0
3 years ago
Which of the following is the correct expansion of (3x-y)2
GREYUIT [131]
6x-2y (I believe so)
4 0
3 years ago
four sisters bought a present for their father. They receive a 10% off discount on the original price o the gift. After the disc
valina [46]

the answer should be $40.00

8 0
3 years ago
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