Hello from MrBillDoesMath!
Answer:
r^4- 29r^2 + 100
Discussion:
Rearrange the terms in the product as follows:
(r+2)(r-2) * (r-5)(r+5) =
(r^2 - 4) * (r^2-25) =
f^4 - (25+4)r^2 + 4*25 =
r^4- 29r^2 + 100
Thank you,
MrB
Hmmmm that’s a Good question
Point I think is the anwser
12 - all divisible by it (2*12=24, 3*12=36, 12*5=60)
8 ÷ (7 - 9) * ( 4 + (-4) ) <--- notice that bolded part.
4 + (-4) = 4 - 4 = 0.
after that, you're pretty much dividing and multiplying by 0, so
whatever ÷ whatever * whatever * 0 = 0.
