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mojhsa [17]
3 years ago
15

What is the solution of 2X+3 > 19​

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

x > 8

Step-by-step explanation:

2x + 3 > 19

2x + 3 - 3 > 19 - 3

2x > 16

2x/2 > 16/2

x >8

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At a local store, Kelly and Martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin
grandymaker [24]

Answer:

9.17

Step-by-step explanation:


6 0
3 years ago
Dashna paid a $20 fee for a booth at an art fair so she could sell her ceramic bowls. She will earn $10 for every ceramic bowl s
katovenus [111]

Answer:

The correct answer is D

Step-by-step explanation:

-20 is your y-intercept and your graph will be increasing

6 0
3 years ago
Scott wants to cover his patio with concrete pavers. If the patio is shaped like a trapezoid whose bases are 11 feet and 13 feet
GenaCL600 [577]

<u><em>Answer:</em></u>

Scott will need 168 ft² of pavers to cover his patio

<u><em>Explanation:</em></u>

Scott wants to cover a trapezoid-shaped patio

<u>This means that:</u>

To get the number of square feet of pavers he'll need, we need to get the area of his patio

<u>Area of trapezium id calculated as follows:</u>

Area = \frac{base_{1}+base_{2}}{2} * height

<u>We are given that:</u>

base₁ = 11 ft

base₂ = 13 ft

height = 14 ft

<u>We now substitute with the givens to get the area as follows:</u>

Area = \frac{11+13}{2} * 14 = 168ft^2

<u>This means that:</u>

Scott will need 168 ft² of pavers to cover his patio

Hope this helps :)

5 0
3 years ago
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em>   ==>   <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==>   <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==>   5<em>x</em> = 0.5

==>   <em>x</em> = 0.1

==>   <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==>   <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0
3 years ago
Add. 8x^2-4x-3+5x^2-2x-6
jekas [21]

Answer:

13 x^2 -6x -9

Step-by-step explanation:

8x^2-4x-3+5x^2-2x-6

Combine like terms

8x^2+5x^2        -4x-2x       -6-3

13 x^2                 -6x             -9

6 0
3 years ago
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