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Ira Lisetskai [31]
3 years ago
11

Helpppppppppppppppppppppppppp

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

3 1/3 divided by 2 3/5 equals 1.28205128 (which would mean your answer for this one should be letter D.

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Solve the equation thanks!
AlladinOne [14]

Answer:

c = \frac{27}{40}

Step-by-step explanation:

To eliminate the fractions, multiply all terms by the lowest common multiple of 8 and 5

The lowest common multiple of 8 and 5 is 40

5 + 40c = 32 ( subtract 5 from both sides )

40c = 27 ( divide both sides by 40 )

c = \frac{27}{40}

8 0
3 years ago
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I need help, 15 points!
Ira Lisetskai [31]

Answer:

3(a + 5b + 7c) and 2x(2 + 5y + 11z)

Step-by-step explanation:

3a + 15b + 21c

3(a + 5b + 7c)

4x + 10xy + 22xz

2x(2 + 5y + 11z)

7 0
3 years ago
Researchers ask a random sample of 1,001 adults nationwide whether they favor or oppose the legalization of marijuana. Fifty-fiv
natima [27]

Answer:

b. It will decrease by a factor of 2

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The lower end of the interval is given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}}

The upper end of the interval is given by:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}}

The length of the interval is the subtraction of the upper end by the lower end, so it is:

L = 2z\sqrt{\frac{\pi(1-\pi)}{n}}

This means that the length is inverse proportional to the square root of the size of the sample.

So, if the sample size is multiplied by 4, the length of the interval is going to decrease by a factor of 2.

4 0
3 years ago
Show the work please
frosja888 [35]

Answer: x = 9/2

Step-by-step explanation: 24 = 4x + 6

7 0
3 years ago
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What is the area of an equilateral triangle with apothem 3
Orlov [11]

Answer:

use formula of equilateral triangle = roots 3/4 a square.

6 0
3 years ago
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