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3 years ago

8

Anita and Maria went to the candy store. Maria bought 5 pieces of fudge and 3 pieces ofbubble gum for a total of $5.70. Anita bo

ught 2 pieces of fudge and 10 pieces of bubblegum for a total of $3.60. Determine the cost of 1 piece of bubble gum.

1 answer:

inn [45]3 years ago

8 0

! piece of Bubblegum costs $0.15 One piece of Fudge costs $1.05

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WHOEVER GETS RIGHT GETS BRAINLIEST!!

ozzi

Answer:

Answer B: min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note: Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term: it is 2.

Take half of that and square your result: (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x + 1 - 1 - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or f(x) = (x - 1)^2 - 6

Compare this to the standard form

f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B: min. value at -6.

3 0

3 years ago

Please help me out with this

AURORKA [14]

6m (m+2) = 0 is the factored form
m=0, m=-2 is m

Steps are on paper
If you need more explanation, comment

4 0

3 years ago

In the winter, a town has a low of -5⁰F. In the summer, the same town has a high of 98⁰F. what is the difference between the tem

wariber [46]

103 is your answer and i gotta put 20 words so dont mind the rest HAKAKALLALAMANANAKALSKDUIWIW

5 0

3 years ago

Find an equation of the line that passes through the point (-6,7) and is perpendicular to the line 12x-18y-72=0

madreJ [45]

Answer:

y=-1.5x-2

Step-by-step explanation:

18y=12x-72

3y=2x-12

y=2/3x-4

Slope=-1.5

7=-6(-1.5)+b

7=9-2

4 0

3 years ago

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

8 0

3 years ago