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Leokris [45]
3 years ago
8

Anita and Maria went to the candy store. Maria bought 5 pieces of fudge and 3 pieces ofbubble gum for a total of $5.70. Anita bo

ught 2 pieces of fudge and 10 pieces of bubblegum for a total of $3.60. Determine the cost of 1 piece of bubble gum.
Mathematics
1 answer:
inn [45]3 years ago
8 0
! piece of Bubblegum costs $0.15 One piece of Fudge costs $1.05
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Which linear inequality is represented by the graph?
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y \leq 1/2x + 2 :)

Step-by-step explanation:

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Which of the following describes the image of a triangle after a dilation that has a scale factor of 5/6
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Answer:

See example below.

Step-by-step explanation:

The image of a triangle will be 5/6 the size. It will be slightly smaller than the original. For example, if the side measurement of the triangle on one side is 12 then the image of the triangle after a dilation will be 12*5/6 = 60/6 = 10.

The new side length is 10 slightly smaller than 12.

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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2 years ago
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