I need help with solving this derivative please (check for picture)

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

So

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

If Ali wears a green shirt then we will take a test if we take a test then everyone will pass the test

tresset_1 [31]

Answer:

yea only ofc

Step-by-step explanation:

3 0

3 years ago

Which of the following angles are supplementary to _1? Plsss Help

dolphi86 [110]

Angle 8 because supplementary is two angles whose sum is 180°.

6 0

3 years ago

Read 2 more answers

if you have a 62 in a class any you do a test that is worth 20 percent of your grade and get a 60 what do you have now

Annette [7]

41 my friend hope this helps my good friend

3 0

3 years ago

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

1 year ago