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valentinak56 [21]
3 years ago
6

You are required to deploy a Docker-based batch application to your VPC in AWS. The application will be used to process both mis

sion-critical data as well as non-essential batch jobs. Which of the following is the most cost-effective option to use in implementing this architecture?
Computers and Technology
1 answer:
leonid [27]3 years ago
8 0

Answer:

The answer for the given question is explain below:-

Explanation:

Using ECS as the container management tool and then set up a mix of Reserved and Spot EC2 Instances for storing mission-critical and non-essential batch jobs.

  • The Control-M jobs have a client descriptor to determine that program server to operate a job on.
  • A load balancing basically used for a host party.
  • We can define an individual server or a server party, all of this is to say a specific name for a network series.
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If a program repeatedly shows separate feature branches rather than a true System Demo, which practice should be reviewed to add
Alenkinab [10]

Answer:

Continuous Integration tool is used to address the issue of separate features branch of program.

Explanation:

Continuous integration process comprise of three main objectives such as improvement, delivery and development of the software. In contentious integration tool all the people  three objective specialist are work together to make program better.

Continuous integration is a platform that is used to detect the problems in a code that need to be corrected. The code is store in the repository of the tool that needs correction. The reviewers review the code in different portions of the code and identify and resolve the problem. There are multiple contributors to correct the code.

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3 years ago
Create an array of strings. Let the user decide how big this array is, but it must have at least 1 element. Prompt them until th
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Answer:

lst = []

n = int(input("Input an array size for you words array: "))

print("Now please enter " + str(n) + " words")

max = 0

min = 1000

index_min = 0

index_max = 0

for i in range(n):

   s = input("Input a word: ")

   lst.append(s)

   if len(s) >= max:

       max = len(s)

       index_max = i

   if len(s) <= min:

       min = len(s)

       index_min = i

print("The longest word is :" + lst[index_max])

print("The shortest word is :" + lst[index_min])

Explanation:

Create an empty list, lst

Get the size from the user

Create a for loop that iterates "size" times

Inside the loop, get the strings from the user and put them in the lst. Find the longest and shortest strings and their indices using if structure.

When the loop is done, print the longest and shortest

5 0
4 years ago
PYTHON!
Lyrx [107]

Answer:

hi Po konbanwa sayo I'm pilipino I'm live in philippines

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How it advances our lives and helps us in so many ways
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