Question

How many solutions does the system have? y=−2x+4

Answer 1

2, you are still solving for x (1) and solving for y (2)

Answer 2

Answer:

There is only one solution and the solution is (0,4).

Step-by-step explanation:

The given system has equations;

$y=-2x+4$

and

$y=x^2-2x+4$

We equate the two equations to determine their point of intersection;

$x^2-2x+4=-2x+4$

$\Rightarrow x^2-2x+2x+4-4=0$

$\Rightarrow x^2=0$

$\Rightarrow x=0$

We put x=0 into the first equation to get;

$y=-2(0)+4=4$

There is only one solution and the solution is (0,4).